2 votes 2 votes Suppose TCP’s additive increase and multiplicative decrease algorithm is used as a congestion control algorithm. The slow start phase begins with 4 MSS and threshold at start of first transmission is 16 MSS. Assume that a time-out occurs during 6 th transmission, what will be the congestion window at 10 th transmission. source: https://gateoverflow.in/2156/gate2012_45 I'm not satisfied with the answer here. Shouldn't it start with 1 MSS again? Computer Networks congestion-control sliding-window + – Warlock lord asked Jan 16, 2018 Warlock lord 595 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer is 10 avadh answered Dec 20, 2018 avadh comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 4mss-8mss-16mss-17mss-18mss-19mss threshold occur 19/2=9 again ,,4mss-8mss-9mss-10mss So total 10 avadh answered Dec 20, 2018 avadh comment Share Follow See all 0 reply Please log in or register to add a comment.