4,217 views

2 Answers

3 votes
3 votes
yes . limit register tell us that we always access under the limits of the process. whenever a request is made of data or instruction in a process. the base address is added with limit register. every request must be less than this address. here i have the largest segment of 2^64 bits so 64 bit will be required. because in worst case i have to check whether the request is crossing the 2^64 segment.
2 votes
2 votes
Answer- 64 bit

Base and limit registers are special hardware registers. When a process is run, the base register is loaded with the physical location where the process begins in memory.

The limit register is loaded with the length of the process. In other words, they define the logical address space.

Related questions

0 votes
0 votes
0 answers
1
SSR17 asked Feb 8
186 views
we have 8 pages (each side 32B) to store in physical memory of 2^32 bits how many bits are required to identify each page , according to me 3 bits are required but that i...
0 votes
0 votes
2 answers
4
Unique_999 asked Aug 17, 2023
293 views
Can Any explain the relationship between The “ Word Size “ and “ Logical Address Space “