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Is the followIng case is possible  rt-s^2 > 0 and r= 0?
closed with the note: Resolved
asked in Calculus by Boss (17.9k points)
closed by | 220 views
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$rt-s^2$, what it means ?
+1
is this what you want to ask?

$rt-s^2>0$ and r=0 is not possible.

it simply means that, $-s^2>0$, which is not possible.
0

thanks, @joshi_nitish.

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