1 votes 1 votes closed with the note: Resolved Is the followIng case is possible rt-s^2 > 0 and r= 0? Calculus engineering-mathematics calculus maxima-minima + – Shubhanshu asked Jan 18, 2018 • closed Oct 7, 2018 by Shubhanshu Shubhanshu 1.1k views comment Share Follow See all 3 Comments See all 3 3 Comments reply joshi_nitish commented Jan 18, 2018 reply Follow Share $rt-s^2$, what it means ? 0 votes 0 votes joshi_nitish commented Jan 18, 2018 reply Follow Share is this what you want to ask? $rt-s^2>0$ and r=0 is not possible. it simply means that, $-s^2>0$, which is not possible. 1 votes 1 votes Shubhanshu commented Jan 18, 2018 reply Follow Share thanks, @joshi_nitish. 0 votes 0 votes Please log in or register to add a comment.