$1)$ $n^{\sqrt{n}}=2^{\sqrt{n}.logn}$
$2)$ $2^{n}$
$3)$ $n^{10}.2^{n/2}=2^{(10.logn+n/2)}$
$4)$ $\frac{n.(n+1)}{2}-1$
Last one is trivial so comparing the exponent part of first $3$.
$\Rightarrow \sqrt{n}logn$
$\Rightarrow n=\sqrt{n}.\sqrt{n}$
$\Rightarrow 10.logn+\frac{n}{2} \approx \frac{n}{2}=\frac{1}{2}(\sqrt{n}.\sqrt{n})$
$\therefore logn<\frac{\sqrt{n}}{2}<\sqrt{n}$
$\Rightarrow$ $1<3<2$
$\color{Red}{4<1<3<2}$