539 views

1 Answer

0 votes
0 votes

kulkarani....i think 20k is corect..

array would be stored in asingle page  like this....

0,0.....0,199

1,0 ....1,199.....loop accessing  array like this....

00F

10H

20F

30H...and so on....means at every access of array there would be one F and one hit.....

and here total 200*200 access and half of the access would be Hit...

so total access 40000/2=20k

Related questions

2 votes
2 votes
0 answers
2
Tuhin Dutta asked Dec 20, 2017
537 views
TLB lookup time = 20 nsTLB hit ratio = 99%Memory access time = 100 nsPage fault rate = 0.05%Swap time = 5000000 nsWhat is the EAT if we assume that all pages currently in...
0 votes
0 votes
2 answers
4
prashant9 asked Jun 15, 2016
6,395 views
(A) processes tend to the I/O-bound(B) size of pages is reduced(C) processes tend to be CPU-bound(D) locality of reference is applicable to the process