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3 votes
3 votes
in how many ways 2 alike apple, 3 alike orange and 4 alike mango can be given to 3 children if each child can have none or 1 or more than 1 fruits.

1 Answer

1 votes
1 votes

n =3  childrens

x1 + x2 + x3 = 2   //apple

r = 2

ways =  $_{r}^{n+r-1}\textrm{C}$ = $_{2}^{4}\textrm{C}$  =  6


x1+x2+x3 =  3  // orange   

r = 3

ways = $_{r}^{n+r-1}\textrm{C}$ = $_{2}^{5}\textrm{C}$   = 10


x1+x2+x3 = 4 // mango

r = 4

 ways  =  $_{r}^{n+r-1}\textrm{C}$  =  $_{4}^{6}\textrm{C}$ = 15


total ways = $6\times 10\times 15 = 900$

Thank you !

edited by

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