1 votes 1 votes amount of time it would take to send 500 packets using 6-packet size window and without sliding window will be, when the time to send in one direction is 5 ms 31000, 5000 4600, 21600 5000, 30000 30000, 5000.......... pls explain the logic behind? gate_forum asked Oct 16, 2015 gate_forum 518 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes With sliding protocol throughput will be n (size of the packet) times of stop and wait(n.B/1+2a).Here without sliding window means simple stop and wait.As n=6,from the option c we can see that 5000 × 6=30000.Hence c will b the answer.Time to send 5 ms i have not considered Rohan Ghosh answered Oct 16, 2015 Rohan Ghosh comment Share Follow See 1 comment See all 1 1 comment reply Arjun commented Oct 16, 2015 reply Follow Share The ratio 1:6 is the reason for the answer? The question doesn't look any where proper. But if you need more standard questions on this topic you can see the links here.. https://gateoverflow.in/blog/27/important-questions-in-computer-networks 0 votes 0 votes Please log in or register to add a comment.
