$T_1 :\color{Red}{r_1(x)}...:\color{blue}{w_1(z)}$
$T_2 :\color{blue}{r_1(z)}...\color{Red}{w_1(x)}$
$\Rightarrow$ Same coloured operation on variables are conflicting therefore only serial schedule is possible so conflict serializability is not possible.
$\Rightarrow$ $\therefore$ Any non serial schedule will form deadlock because $2$pl maintain seriablizability and this schedule is not even possible to have interleaved operation.