2 votes 2 votes Answer given is 24 which is the no. of serial schedules possible, but my doubt is since no two transactions share same variables then all the schedules possible will be conflict serializable then why only serial schedules are considered ? Databases ace-test-series databases transaction-and-concurrency conflict-serializable + – ashish pal asked Jan 26, 2018 • edited Mar 3, 2019 by I_am_winner ashish pal 462 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply RiteshSingh commented Jun 25, 2018 reply Follow Share same doubt yrr someone plz explain.... 0 votes 0 votes Prateek Raghuvanshi commented Aug 3, 2018 reply Follow Share no two transaction sharing the data item then all transaction are independent to each other then all transaction can execute in any manner so 4 transaction each with 4 elements so total no. of conflict serializable schedule =$\frac{16!}{4!*4!*4!*4!}$ 0 votes 0 votes Please log in or register to add a comment.
