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Ace Test Series: Computer Networks - Packet Switching With Pipelining

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packet size=1000bits

message size=100000bits

No of packets=100000/1000=100 packets

Tp=250 sec

Tt=1000/100=10 sec

[Ha]----(R1)----(R2)----[Hb]

For first packet

pkt1 |Tt|Tp|Tt|Tp|Tt|Tp|

pkt1 10-250-10-250-10-250

pkt2 started 10 sec after pkt1 as Tt ant overlapped so pkt2 is delayed by Tt,similarly pkt3 is delayed by 2.Tt from pkt1 and so on 

Total time=first packet+99 packets

               =(3*Tt+3*Tp)+(99*Tt)

               =780+990

               =1770 sec  

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