ANSWER FOR 2ND IS 12KB.
FORMAT OF CONTROL WORD IS
branch cond'n |
flags |
control field |
memory address |
And the control word size is 24b or 3B.
number of bits required for mem address = 24 -{ branch bits +flags bits + control fied )
= 24 -( 0+log16+log250) =12 bits
It means there are 212 addresable memory and each address stores control word .
So the total control mem size = 2^12 *3B = 12 KB{ANS}