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Can someone explain me these two qns and solution :)

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ANSWER FOR 2ND IS 12KB.

FORMAT OF CONTROL WORD IS

branch cond'n flags control field memory address

        And the control word size is 24b or 3B.

number of bits required for mem address = 24 -{ branch bits +flags bits + control fied )

                                                             = 24 -( 0+log16+log250)  =12 bits

It means there are 212 addresable memory and each address stores control word .

So the total control mem size = 2^12 *3B =   12 KB{ANS}

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