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What is mean here by word size=4 Byte ?

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Word addressable. Which means 224 words is the physical address memory not bytes.

But please someone solve this question. The solution given is not clear.

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..let node down all the parameter first...

line/block size=128byte/4=32word=25   .word

tag memory size is....211  bytes or 29 word  ...

offset       tag      Set

5               x         19-x

then tag memory size is...=tag*lines

x*219-x+4 bits/ 4byte  = 29word

x*219-x+4-3-2=18-x  word=.29word

x*218-x  29  ...(problem how to decide the value of x..)

vale of x=13..then answer would not matched....

case 2:-

if we assume that tag memory = equal to 2tag bits    ....

that is also not matching with given scenario...

:- Note:- in my openion this question having lack of information

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Yes after converting everything to word addressible i also got stuck where @hs is! Because that equation can’t be solved! :( lack of information or questions arrangement is wrong i guess
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Thank you @ hs_yadav and @ Ashwin Kulkarni

how to calculate cache m/m size? and tag m/m size
by Active (1.1k points)

+1 vote