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What is mean here by word size=4 Byte ?

Please solve the below question

in CO and Architecture by Junior (875 points) | 89 views
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Word addressable. Which means 224 words is the physical address memory not bytes.

But please someone solve this question. The solution given is not clear.

+1

..let node down all the parameter first...

physical address is 24 bits...

line/block size=128byte/4=32word=25   .word

tag memory size is....211  bytes or 29 word  ...

physical address partision...

offset       tag      Set

5               x         19-x

then tag memory size is...=tag*lines

          x*219-x+4 bits/ 4byte  = 29word  

          x*219-x+4-3-2=18-x  word=.29word    

         x*218-x  29  ...(problem how to decide the value of x..)

vale of x=13..then answer would not matched....

case 2:- 

if we assume that tag memory = equal to 2tag bits    ....

that is also not matching with given scenario...

:- Note:- in my openion this question having lack of information

0
Yes after converting everything to word addressible i also got stuck where @hs is! Because that equation can’t be solved! :( lack of information or questions arrangement is wrong i guess
0

Thank you @ hs_yadav and @ Ashwin Kulkarni

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