1,571 views
1 votes
1 votes
In a bunch of $13$ T-shirts only $1$ is of Medium size, which is correct fit for the searching person.

Each time wrong size is picked, the person throws it away and pick the next T-shirt.

What is the probability that the correct size T-shirt can be searched in $8^{th}$ attempt ?

My attempt : $\frac{1}{13}$ where i went wrong ?

3 Answers

0 votes
0 votes

Let Li be the event of searching medium sized T-shirt in ith attempt. P(L'1 ∩ L'2 ∩ L'3 ∩ L'4 ∩ L'5 ∩ L'6 ∩ L'7 ∩ L8 ) = P(L'1) . P(L'2 / L'1) . P(L'3 / L'1 ∩ L'2) ------- P( L8 / L'1 ∩ L'2 ...... L'7) = 8/13 . 7/12. 6/11. 5/10. 4/9. 3/8. 2/7. 1/6 = 40320 / 51891840 = 1 / 1287.... answer given was this how can this be the answer

0 votes
0 votes

The question and the answer are both a bit clumsy here.

They are saying, than the T-shirt can be found in eighth attempt. No one knows if they wanna say, 

  • The selection process puts the shirts into a random order, and we have a "success" if the shirt is in any of the first eight positions (first interpretation).
  • Or under the assumption that "success" means finding the medium shirt only on the eighth attempt, not earlier.

The word CAN here doesn't signifies surety.

The proposed solution on the website makes the absurd claim that the probability not to find a medium shirt on the first attempt is 8/13. That would be the correct probability if the problem statement said there were five medium shirts, but the problem statement clearly says there is only one. Hence the correct probability is 12/13. The remaining probabilities are as 11/12 * 10/11* 9/10....and so on.

(Under the assumption that "success" means finding the medium shirt only on the eighth attempt, not earlier)  the probability to be in the eighth position is 1/13

Now, by directly computing P(L′1∩L′2∩L′3∩L′4∩L′5∩L′6∩L′7∩L8) as proposed in the solution on the website,  it is attributable to the fact that we computed the probabilities correctly and they gave the wrong probabilities. You need only make the obvious cancellations in order to obtain a simple fraction as the solution.

Still we can't give a correct solution to an incorrect question.  So I guess, everyone's assumption would be right here. And marks should be given to all.

0 votes
0 votes
Here,we are given 13 shirts and the man throws them one by one if they do not fit.

So,we can do this by binomial distribution.

n=8 ( no of trials)

 

x=1( no of times the trial needs to get succeeded i.e if 1 shirt fits then work is done )

 

p=probability of success = 1/8 , since we are doing it for 8 attempts so total no of shirts that would be taken into account are 8

 

q = probability of failure= 7/8, since only 1 shirt which is medium size will fit

 

put them in formula i.e (nCx *p^x*q^n-x)

 

therefore I think the answer is 0.39 which is

 

5/13.

Related questions

2 votes
2 votes
1 answer
2
practicalmetal asked Jan 3
222 views
8 pairs of hand gloves are on a shelf ( each of different colour). Four gloves are selected at random, the probability that there will be at least one pair is?