Data=10500B
pkt size=1500B (including 40B header)
data in each packet= 1500-40=1460B
No of pkts required=105000/1460=71.9
That is 72 pkts in all.
Tt (Ato B)= length of pkt/BW = (1500*8)/(100*10^6)= 0.00012 sec
Tt(B to A)= lenght of ack pkt / BW = (40*8)/(100*10^8)=0.0000032 sec
Total time for one pkt =Tt (Ato B) + Tt(B to A) + Tp*2= 0.0101232 sec
Total time for all pkts = 72*(Tt (Ato B) + Tt(B to A) + Tp*2)= 0.7288704 sec
Throughput = Data sent / Time taken = 105KB/0.7288704 = 144.06 KBps