28 votes 28 votes Which one of the following Boolean expressions is NOT a tautology? $((\,a\,\to\,b\,)\,\wedge\,(\,b\,\to\,c))\,\to\,(\,a\,\to\,c)$ $(\,a\,\to\,c\,)\,\to\,(\,\sim b\,\to\,(a\,\wedge\,c))$ $(\,a\,\wedge\,b\,\wedge\,c)\,\to\,(\,c\vee\,a)$ $a\,\to\,(b\,\to\,a)$ Mathematical Logic gatecse-2014-set2 mathematical-logic propositional-logic normal + – go_editor asked Sep 28, 2014 • edited Jun 25, 2017 by Silpa go_editor 9.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes we can also solve it by satisfying the T(try to make LHS true) and F(try to make RHS False) condition of ->(implication), if it satisfied then it is NOT tautology. if it is not then it is Tautology. Answer is B Nikhil Prasad answered Jun 23, 2016 Nikhil Prasad comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊 akshay_123 answered Sep 13, 2023 akshay_123 comment Share Follow See all 0 reply Please log in or register to add a comment.
