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The average of 4 distinct prime numbers a, b, c, d is 35 where a < b < c < d. b and c are equidistant from 34 and; a and b are equidistant from 30 and; c and d are equidistant from 40; a and d are equidistant from 36 . The difference between a and d is?
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From the given data a<30, 30<b<34, 34<c<40, d>40. Hence b should be 31(only prime between 30 and 34) and thus a=29,c =37,d=43. Diff of a and d = 14.
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