Question

Find First and Follow of the given grammar

$S \rightarrow aSa | bSb|A$

$A \rightarrow aBb$

$B \rightarrow aB|bB|\epsilon$

Comments

S= first={a,b},follow={a,b,$}

A=first={a},,follow=follow of S

B=first={a,b,null},follow={b}

Answer 1

Here it is ......

Comments

yes,

for B, to get b, we can use

$B \rightarrow bB$ and

$B \rightarrow \epsilon$

and hence it is not $LL(1)$

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Yes this answers is correct but LL(1) Parsing table will be create also

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can you help me with other grammar please?