gate 2018

Question

consider the computer system with two byte instruction and has $16$ instruction registers and $64$ floating point registers.

type 1

type 2

type 3

type 4 has N instructions requiring 1 floating point register  each

what is the value of N?

Comments

i got 256..

Answer 1

The answer would be 1024.

Answer 2

16-bit instruction,since there are 4 -types ,2 bits must go for identifying them.Then we are left with 14 bits,out of again which 6 bits go for the floating point register and we are then left with 8 bits.

So N value must be 2^8=256.