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**(C) 1.5 : 1**

2011:

- $m{_1}$ = no of male students
- $f{_1}$ = no of female students
- $\dfrac{m{_1}}{f{_1}}=1$

2012:

- $m{_2}$ = no of male students
- $f{_2}$ = no of female students
- $\dfrac{m{_2}}{f{_2}}=1.5$

Given : $f{_1}=f{_2}=f$

So , $\dfrac{m{_1}}{f}=1$ and $\dfrac{m{_2}}{f}=1.5$

$f=\dfrac{m{_1}}{1}$ and $f=\dfrac{m{_2}}{1.5}$

Both the equations can be equated.

$\dfrac{m{_1}}{1} =\dfrac{m{_2}}{1.5}$

**Ratio of male students in 2012 to male students in 2011** $\Rightarrow \dfrac{m{_2}}{m{_1}} =\dfrac{1.5}{1} = 1.5 : 1$