why (0.M) and not (1.M) ?

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A 32-bit floating-point number is represented by a 7-bit signed exponent, and a 24-bit fractional mantissa. The base of the scale factor is 16,

The range of the exponent is ___________, if the scale factor is represented in excess-64 format.

The range of the exponent is ___________, if the scale factor is represented in excess-64 format.

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Best answer

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It is asked , range of the exponent in excess 64 format , i.e. double precession format

Single Precession: SEEEEEEE EMMMMMMM MMMMMMMM MMMMMMMM Double Precession: SEEEEEEE EEEEMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM

Now for positive or negative normalize real number exponent range must be in between 000.....01 to 11.....10

Now for single precession it will be 0000 0001 to 1111 1110

and in double precession it will be 0000 0000 001 to 1111 1111 110

http://steve.hollasch.net/cgindex/coding/ieeefloat.html

https://gateoverflow.in/194521/dl-ieee-754-single-precision-range

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