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A 32-bit floating-point number is represented by a 7-bit signed exponent, and a 24-bit fractional mantissa. The base of the scale factor is 16,

The range of the exponent is ___________, if the scale factor is represented in excess-64 format.
asked in Digital Logic by Veteran (98.5k points) | 156 views

2 Answers

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Range = 2^126 to 2^127
answered by Junior (607 points)
0
exponent will be in between 00000001 to 11111110

right?
0 votes

It is asked , range of the exponent in excess 64 format , i.e. double precession format

Single Precession: SEEEEEEE EMMMMMMM MMMMMMMM MMMMMMMM
Double Precession: SEEEEEEE EEEEMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM MMMMMMMM

Now for positive or negative normalize real number exponent range must be in between 000.....01  to 11.....10

Now for single precession it will be 0000 0001 to 1111 1110

and in double precession it will be 0000 0000 001 to 1111 1111 110

http://steve.hollasch.net/cgindex/coding/ieeefloat.html

https://gateoverflow.in/194521/dl-ieee-754-single-precision-range

https://gateoverflow.in/82469/coa-floating-point-arithmatic

answered by Veteran (86.8k points)
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