2 votes 2 votes Conjecture a simple formula for an if the first few terms are 1,2,2,2,2,3,3,3,3,3,3,3,3,3,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4 Set Theory & Algebra sequence-series + – Mk Utkarsh asked Feb 12, 2018 Mk Utkarsh 391 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Neeraj Chandrakar commented Mar 8, 2018 reply Follow Share No of times $n^{th}$ no appears in sequence is is $n^{{2^{n}}}$ 0 votes 0 votes Mk Utkarsh commented Mar 8, 2018 i edited by Mk Utkarsh Mar 8, 2018 reply Follow Share also the range of $n^{th} $ term is $\left [ \frac{\left ( n-1 \right )n\left ( 2n-1 \right )}{6}+1, \frac{\left ( n \right )\left ( n+1 \right )\left ( 2n+1 \right )}{6} \right ]$ 0 votes 0 votes Mk Utkarsh commented Mar 8, 2018 reply Follow Share but simple formula for an? 0 votes 0 votes Sukannya commented Mar 8, 2018 reply Follow Share 1*1=1, 1 appears 1 time, 2*2=4, 2 appears 4 times, 3*3=9, 3 appears 9 times, so a number repeats n*n times 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 1 square is 1 so 1 is written once 2 square is 4 so 2 is written 4 times 3 square is 9 so 3 is written 9 times and it goes so on phani143 answered Mar 21, 2019 phani143 comment Share Follow See all 0 reply Please log in or register to add a comment.