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Best answer

Let $n$ be the smallest number which is divisible by $x, y$ and $z$ and leaves remainder $r$ in each case.

So$, n = LCM ( x , y , z ) + r$

`According to Question`

$x = 20 , y = 42 , z = 76$ and $r = 7$

Smallest number, $n = LCM (20, 42, 76 ) + 7$

$\implies n = 7980 + 7 = 7987$

So, option (C) is the right choice

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