retagged by
6,147 views
16 votes
16 votes

In a party, $60\%$ of the invited guests are male and $40\%$ are female.If $80\%$ of the invited guests attended the party and if all the invited female guests attended, what would be the ratio of males to females among the attendees in the party?

  1. $2\colon 3$
  2. $1\colon 1$
  3. $3\colon 2$
  4. $2\colon 1$
retagged by

6 Answers

Best answer
29 votes
29 votes
Assume $100$ people are invited, so $60$ men and $40$ women invited.

During the party only $80$ people showed up, and since all women attended $\Rightarrow 80 = 40 +$ men

Therefore, men $= 40$

men : women $= 1:1$

Correct Answer: $B$
edited by
8 votes
8 votes

Answer is B-  1:1 

Lets consider total guests are x.

then,

5 votes
5 votes
Lets say 100 people are invited.
60 male, 40 female.

Total 80 people came.
All female came too.
So x+40= 80
=> x = 40 male came.

Male/Female = 1:1
2 votes
2 votes
suppose there are 100 people then

men =60

women=40

as all women attend so 20 men did not attend party

so men=40

women=40

so 1:1
Answer:

Related questions

15 votes
15 votes
10 answers
1
gatecse asked Feb 14, 2018
7,304 views
If $pqr \ne 0$ and $p^{-x}=\dfrac{1}{q},q^{-y}=\dfrac{1}{r},r^{-z}=\dfrac{1}{p},$ what is the value of the product $xyz$ ?$-1$$\dfrac{1}{pqr}$$1$$pqr$
14 votes
14 votes
2 answers
2
Arjun asked Feb 18, 2021
10,487 views
The number of students in three classes is in the ratio $3:13:6$. If $18$ students are added to each class, the ratio changes to $15:35:21$.The total number of students i...
29 votes
29 votes
4 answers
4
gatecse asked Feb 14, 2018
10,589 views
In the figure below, $\angle DEC + \angle BFC$ is equal to _____$\angle BCD - \angle BAD$$\angle BAD + \angle BCF$$\angle BAD + \angle BCD$$\angle CBA + \angle ADC$