GATE CSE 2018 | Question: GA-8

Question

In a party, $60\%$ of the invited guests are male and $40\%$ are female.If $80\%$ of the invited guests attended the party and if all the invited female guests attended, what would be the ratio of males to females among the attendees in the party?

• A. $2\colon 3$
• B. $1\colon 1$
• C. $3\colon 2$
• D. $2\colon 1$

Comments

1:1

I assumed 100 people

60 male

40 female

80 came

All females were these. Thus 40 female

Hence 40 male

So 1:1

Answer 1

$\text{Let no of males  M = 6k,no of females F= 4k then total no of guests = 10k (where k is a constant)}$

$\text{no of guests attended}$ = $\text{80% of total guests}$

$\implies X * 6k + 1 * 4k = 0.8 * 10k$

$\implies 6*X  = 4$

$\therefore \text{M:F } = X*6k : 1*4k = 6X : 4 =  4:4 = 1:1 $ 

Answer 2

1:1

I thought 40% of 80%