Answer - A.
Quick logic review -
$\alpha : \forall x \exists y \hspace{.5em}y<x$
Is $\alpha$ true for domain of all integers ?, Yes it is true. You pick any number $x$, I can always give you $y$ that is less than your number $x$.
Is $\alpha$ true for domain of Non Negative integers $\{0, 1,2,3,\dots\}$ ? No, it is not true. (You pick any number $x$) If you pick $0$ then I can not give you $y$ which is less than $0$.
Definition of $\text{Model }$ - Domain for which my sentence is true. For above sentence $\alpha$, all integers is model and there can be many other models, like - real numbers.
(Definition of $\text{Co Model }$- Domain for which my sentence is False.)
Given that Predicate $\Phi \equiv \exists s \exists t \exists u \forall v \forall w \forall x \forall y \Psi (s,t,u,v,w,x,y)$ has a model with universe containing 7 elements. I.e. there is a domain with 7 elements which satisfies my $\Phi$ .
Now let $\Phi \equiv \exists s \exists t \exists u \forall v \forall w \forall x \forall y \hspace{.5em} s+t+u+v+w+x+y \gt 200$. Can you suggest me a set (domain) that is model for $\Phi$ ?. (i.e. the domain for which you can satisfy $\Phi$ ).
$\{10,20,30,40,50,60,100\}$, now if I choose $s=50$, $t=60$ and $u=100$ $^{[1]}$ and let anyone choose values of $v, u ,x \text{ and } y$ then $\Phi$ is always satisfiable for any values (or write like this - for all values) of $v, u ,x \text{ and } y$ . The key point is you have to choose values of $ s ,t \text{ and } u$ carefully and once u fixed these values then it should work for all remaining universal quantifiers values.
Actually I have problem with first element of set "$10$". Can I remove it and the resultant set will still work as model ? $\{20,30,40,50,60,100\}$, Of course this is model for $\Phi$ (Why ? - take $s=50$, $t=60$ and $u=100$ and let any other variable value be anything).
Similarly, $\{50,60,100\}$ is also model for $\Phi$.
Idea is once you have your $\bf{s, t \text{ and } u}$ in set then that set is model (because remaining quantifiers can take any value).
Even the singleton set $\{100\}$ is also model for $\Phi$.
Now there is always one model of universe size $3$, and depending on your predicate you can have model of less than size $3$ too (like above singleton set).
$^1$ $s=t=u=100$ also works.
Now, Lets generalize this for better understanding-
let $\Phi$ has following model of size 7- $\{e_1,e_2,e_3,e_4,e_5,e_6,e_7\}$, and let $s=e_2, t=e_5, u=e_1$ is the only setting which works for any (for all) values of $v,w,x \text{ and }y$, then Can we reduce model size ?- Yes, we can have a model of size 3 $\{e_1,e_2,e_5\}$. Can we reduce size further ?- We can not ( Because $s=e_2, t=e_5, u=e_1$ is the only setting which works for any value of $v,w,x,y)$. But if $s = t$ or $t = u,$ we can even have a model of size less than $3.$