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7 Answers

Best answer
121 votes
121 votes
$P(X) = x^5 + 4x^3 + 6x + 5$

$=x(x^4 + 4x^2 + 6) +5$

$=x( x ( x^3 + 4x) + 6) + 5$

$=x( x ( x (x^2 + 4)) + 6) + 5$

$=x( x ( x (x(x) + 4)) + 6) + 5$

mul = pair of brackets $4$
add = num of signs $3$
total $7$
edited by
25 votes
25 votes

In the above 8 steps of evaluation, the total number of arithmetic operations required are 7 [4
Multiplications, 3 Additions]
So answer is 7 arithmetic operations.

17 votes
17 votes

x5+4x3​+6x+5 = x3(x2+4)​+6x+5
x3 -> 3 multiply operations (also gives x2)

So, Totally we need 3 + 1 multiplications and 3 additions = 7 operations

7 votes
7 votes

P(X) = X5+4X3+6X+5

RHS

X(X4+4X2+6)+5

X(((X2)2+2.2.X2+22)+2)+5

X((X2+2)2+2)+5

Now:

T=X*X

T=T+2

T=T*T

T=T+2

T=T*X

T=T+5

Therefore - (* operator used) =3, (+ operator used) = 3 Total=6

Answer:

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