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Arrange the following three-dimensional objects in the descending order of their volumes:

1.    A cuboid with dimensions $\text{10 cm, 8 cm and 6 cm}$
2.    A cube of side $\text{8 cm}$
3.    A cylinder with base radius $\text{7 cm}$ and height $\text{7 cm}$
4.    A sphere of radius $\text{7 cm}$
1. $\text{i), ii), iii), iv)}$
2. $\text{ii), i), iv), iii)}$
3. $\text{iii), ii), i), iv)}$
4. $\text{iv), iii), ii), i)}$

Volume of each one is:

1. $V_{\text{cuboid}} = l*b*h = 10 * 8 * 6 = 480\ cm^2$
2. $V_{\text{cube}} = a^3 = 8^3 = 512\ cm^2$
3. $V_{\text{cylinder}} = \pi r^2h \approx 1077.57\ cm^2$
4. $V_{\text{sphere}} = \frac{4}{3} \pi r^3 \approx 1436.76\ cm^2$

So, the descending order is:

(D) (iv), (iii), (ii), (i)

## Vol of cuboid: L * B * H

=  10 * 8 * 6 = 480 cm3

## Vol of cube: L3

= 83

= 512 cm3

## Vol of cylinder: π*h*r2

= 1077.566 cm3

## Vol of a sphere: 4/3*π*r3

= 1436.755 cm3

So, descending order is (IV), (III), (ii) and (i)

option D