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C) Area of equilateral triangle is given by $\frac{\sqrt{3}}{4}a^2\ =\ \sqrt{3}\\a\ =\ 2\\Perimeter\ =\ 3a\ =\ 6$
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We know the area of an equilateral Triangle$= \frac{\sqrt3}{4} \ a^2 $

Where 'a' is length of sides of  triangle.

so by given condition 9

$\frac{\sqrt3}{4} \ a^2 = \sqrt 3$

i.e $a^2 =4 $ so $a=2$

Perimeter$=3*a=3*2=6$

So option (C) is Correct.

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