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GATE2018 EC: GA-3

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Divisibility rule of 3: 

A number is divisible by 3 if sum of its digits is divisible by 3.

Let the digit in thousands place be $x$.

$7+1+5+x+4+2+3= 22+x$

Smallest possible value of $x$ so that the sum is divisible by $3$ is $2$ ($24\mod 3=0$)

Hence option (B) is correct answer

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