Answer should be (C)
Here , F(A, B, C) = A̅⋅ B̅ ⋅ C̅+ A̅⋅ B ⋅ C̅+ A ⋅ B̅ ⋅ C̅ .Since it is written in Sum of Products(SoP) and It contains minterms as m0 , m2 , m4 . So , We can write F(A, B, C) as Σ(0,2,4) .it means in truth table, F(A,B,C) is '1' when decimal equivalent of (A,B,C) is 0,2,4 . So, in other positions ie. 1,3,5,6,7 F(A, B, C) should be '0' .
So, Simply , F(A, B, C) = Σ(0,2,4) = π (1,3,5,6,7)
Here , π (1,3,5,7,8) means We have maxterms as M1 ,M3 ,M5 ,M7 ,M8 . So , F(A,B,C) can be written in Product of Sum(PoS) as F = (A + B + C̅) ⋅ (A + B̅ + C̅) ⋅ (A̅+ B + C̅) ⋅ (A̅+ B̅ + C) ⋅ (A̅+ B̅ + C̅)