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7 votes
7 votes
Find the remainder $\dfrac{(39)^{42}}{10}$
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3 Answers

Best answer
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6 votes

Calculate Euler Totient number of $10=2*5$ i.e $\phi(10)= 10*(1-\frac{1}{2})*(1-\frac{1}{5})$

$\phi(10)= 4$

Using remainder theorem:

$\frac{rem(\frac{39}{10})^{rem({\frac{42}{4}})}}{10}$

$\frac{{9}^{2}}{10}= \frac{81}{10}=1(rem)$

Hence 1 is the correct answer

https://www.mbatious.com/topic/61/remainder-theorem

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3 votes
3 votes

You are dividing a number by 10.This means if the number is divisible 10 then it will leave remainder 0 and if not then it will leave the last digit as remainder.

The unit's place of 39 is 9. 3942 means you are multiplying 39 for 42 times.

39 x 39 = y ,where the unit place of y is 1 because 9x9 =81 and unit place of 81 = 1

39 x 39 x 39 = 39 x y = z ,where the unit place of z is 9. Previously y = 1.Multiply 1 x 9 is same as 9.

so

39a % 10 = 1 when a is even

39a % 10 = 9 when a is odd

Here a = 42 =even

Hence remainder will be 1

ANSWER = 1

1 votes
1 votes

(3942)/10 in this problem reminder is 1.

You think this way --> 39*39*39......39

 now  the reminder term depends upon the least significant digit because of denominator 10.

So for 9*9*9*9.......9 now for 9i where i=2n+1 the least significant digit is 9 so reminder is 9 and for all 9i where i=2n least dignificant digit is 1 so reminder is 1.

So in our question 942=92n where n=21,

Ans is 1.

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