Considering h as height of tree, h =0 at root. Total no of elements are (2^(h+1)-1) means it is complete.Largest element wil be in leaf level of MIN HEAP.
At each level we have two choices (i.e paths to take equally likely) to reach bottom we have(2*2*2.....*2) h times,among all choices only one will lead to largest element. SO, probability to reach largest element while traversing tree is 1/2^h.