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Consider a $3$ digit number

  1.  All digit are distinct
  2. Number is divisible by $7$
  3. After reversing the digit number is also divisible by $7$.

How many such numbers are possible?

  1. $4$
  2. $5$
  3. $6$
  4. $7$
in Numerical Ability by Boss (44.4k points)
edited by | 187 views
0
4 ??
0
Yes 4 is the answer
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@Srestha , All digits are distinct..
0
168,259 and reverse of it also count as 3 digit numbers
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but how to get 168, 259?
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Thanks Mk bhai
0
i don't understand how people think like that :o
check the answer bro :o
0
Answer is 4
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yeah i know
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Actually there are 2 numbers

1x8, 2y9

and then their reverse

And now by brute force put some value in x and y and check they are divisible by 7 or not

Answer of stackoverflow some printing mistake is there

it will be 168, 259,952,861
0
yeah it should be 861 you're right

he made a typo there
0
If you haven't heard about it then only brute force can help you

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