candidate key

Question

Given relation R(A,B,C,,DE,F) with FDs

C->A

DE->F

B->D

ADD C->B  to following FD.. How many different FD are there which make C as candidate key...(For simplicity assume FD have only one attribute on LHS and RHS)

 

 

Answer 1

can add A->E,

to make c as c.k,so no. of f.d reqd=5