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As first and last position is fixed , we can only manipulate the middle 6 positions

P  __   __   __   __   __   __  R

We have 6 positions and 6 letters left ( E , C , U , L , I , A )

So, we have $^6P_6$ (as we have to select & then arrange) or 6! or 720 different ways to fill the middle 6 places

∴ 720 different words can be formed out of the letters of the word "PECULIAR"  beginning with P and ending with R.

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6!

As postion of P and R is fixed

So 1 way for there arrangement and rest of the digits could be arranged in 6! ways
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