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Output of the program
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closed as a duplicate of: Undefined Behaviour in C 
#include<stdio.h>
int main()
{
    char a[]={'A','B','C','D'};
    char *p=&a[0];
    *p++;
    printf("%c%c",*++p,--*p);
}

What will be the output?

1)C B

2)B B

3)B A

4)C A

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