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27 votes

The above synchronous sequential circuit built using JK flip-flops is initialized with $Q_2Q_1Q_0 = 000$. The state sequence for this circuit for the next $3$ clock cycles is

  1. $001, 010, 011$
  2. $111, 110, 101$
  3. $100, 110, 111$
  4. $100, 011, 001$
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5 Answers

6 votes
6 votes

JK ff truth table---

j k Q
0 0 Q0
1 0 1
0 1 0
1 1 Q0’

Initially Q2Q1Q0=000 Present state FF input                   Next state

Q2 Q1 Q0 J2 K2 J1 K1 J0 K0 Q2 Q1 Q0
0 0 0 1 0 0 1 0 1 1 0 0
1 0 0 1 0 1 0 0 1 1 1 0
1 1 0 0 0 1 0 1 1 1 1 1
                       

So ans is ( C) part.

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0 votes
Although given answer is correct one thing worth to be noted here as it's "asynchronous circuit" and given "sign" of clock plus (-o>) which is "negative level trigger" {1-->0}
So when Q2 value change form 1-->0 Q1 gets complemented
Answer:

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