jjayantamahata
asked
Apr 16, 2018
210
views
ISI-2004-30
If the tangent at the point $P$ with co-ordinates $(h, k)$ on the curve $y^2 = 2x^3$ is perpendicular to the straight line $4x=3y$, then $(h, k) = (0,0)$ $(h, k) = (1/8, -1/16)$ $(h, k) = (0,0)$ or $(h, k) = (1/8, -1/16)$ no such point $(h, k)$ exists.
If the tangent at the point $P$ with co-ordinates $(h, k)$ on the curve $y^2 = 2x^3$ is perpendicular to the straight line $4x=3y$, then$(h, k) = (0,0)$$(h, k) = (1/8, -1...
