1 votes 1 votes Let $A = (a_{ij})_{n\times n}$ such that $a_{ij}=3$ for all $i,j$ then nullity of $A$ is $n-1$ $n-3$ $n$ $0$ Linear Algebra matrix nullity-of-matrix + – Avik Chowdhury asked Mar 22, 2018 • edited Mar 23, 2018 by Sukanya Das Avik Chowdhury 2.5k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply MiNiPanda commented Mar 23, 2018 reply Follow Share I didn't get the matrix A's expression properly. Is it that all the elements of the matrix A which is of order 'n' is aij (where aij=3) ? 0 votes 0 votes ankitgupta.1729 commented Mar 23, 2018 reply Follow Share yes ..all the elements of this matrix = 3..So , rank of this matrix A = 1 ..Since , rank(A) + nullity (A) = no. of columns in A.. So, 1 + nullity(A) = n ...So, nullity(A) = n - 1 1 votes 1 votes MiNiPanda commented Mar 23, 2018 reply Follow Share Yes then it's (n-1). 1 votes 1 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes nullity= number of columns of A- rank of matrix. abhishekmehta4u answered Mar 23, 2018 • selected Mar 23, 2018 by Avik Chowdhury abhishekmehta4u comment Share Follow See all 0 reply Please log in or register to add a comment.