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Let $A$ be a $3\times 3$ matrix with Eigen values $-1,1,0$.Then $\mid A^{100}+I\mid$ is...
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EIGEN VALUES OF A^(100) will be (-1)^(100)=1

(1)^(100) =1 , (0)^(100)=0, det|A^(100)+ I| = 2*2*1 =4

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Nishant Arora asked Dec 15, 2016
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can we use some identity to find value of ab+by+ya???without finding its eigen values and then multiplying..earlier i have read it somewhere but i forget it.