Operating Systems Paging

Question

Using the page table shown below, translate the physical address $25$ to virtual address. The address length is $16$ bits and page size is $2048$ words while the size of the physical memory is four frames.

Page	Present (1-In, 0-out)	Frame
$0$	$1$	$3$
$1$	$1$	$2$
$2$	$1$	$0$
$3$	$0$	-

• A. $25$
• B. $6169$
• C. $2073$
• D. $4121$

How to solve this

Comments

then what that 25 is?

Is it wrongly typed?

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25 is value of physical address.. My friend asked this question

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ok :)

Answer 1

check this solution @srestha. i have done this assuming that 16 bits is legth of virtual address. And for 4 frames (as given in ques we require 2 bits for frames)

correct me if i'm wrong in concept.

Comments

4121 is correct :)

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ya, corrct soln :)