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In a class of $80$ students, $40$ are girls and $40$ are boys. Also, exactly $50$ students wear glasses. Then the set of all possible number of boys without glasses is

  1. $\{0,.....,30\}$
  2. $\{10,....,30\}$
  3. $\{0,.....,40\}$
  4. $\text{none of these}$
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Among $80$ students $50$ students wear glasses.

Now, we have to find out set of all possible numbers without glasses 

No. of students wear glasses-

  1. When Girls = $10$, Boys = $40 \text{ Remaining Boys without glasses=}0 \rightarrow \text{ possible}$
  2. When Girls = $20$, Boys = $30 \text{ Remaining Boys without glasses=}10 \rightarrow \text{ possible}$
  3. When Girls = $25$, Boys = $25 \text{ Remaining Boys without glasses=}15\rightarrow \text{ possible}$
  4. When Girls = $30$, Boys = $20 \text{ Remaining Boys without glasses=}20 \rightarrow \text{ possible}$
  5. When Girls = $40$, Boys = $10 \text{ Remaining Boys without glasses=}30 \rightarrow \text{ possible}$
  6. If  Boys = $0$, then Girls = $50  \rightarrow \text{ not possible as Total girls is 40}$

$∴\color{green}{\text{ Answer will be}} \color{Purple}{\text{ option A) }} \color{pink}{ \{0,....30\}}$

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