#Algorithms minimum number of comparisons required to find the minimum and the maximum of 101 numbers?

Question

The minimum number of comparisons required to find the minimum and the maximum of 101 numbers is ________.

When n is even then it's relatively easy, but how to deal with n is odd?

My answer is 150 comparisons.

Answer 1

150 comparisons

Comments

Thanks bhai, ek baar phir se.

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We can also do it by using tournament method.

Answer 2

https://www.youtube.com/watch?v=dEyRl9Tj83g

please refer this video.

and this link https://www.geeksforgeeks.org/maximum-and-minimum-in-an-array/

Comments

Thanks! :)