Total number of possible combinations = 3*3 = 9
r = 2 (1,1)
r = 3 (1,2) , (2,1)
r = 4 (1,3) , (2,2) , (3,1)
r = 5 (3,2) , (2,3)
r = 6 (3,3)
P(r >=4) = 6/9
P(r <=4) = 6/9
P(r <=3) = 3/9
P(r > 5) = 1/9
P(r =4) = 3/9
P(r >=4) = P(r <=4) = 6/9
Option A is correct