0 votes 0 votes jjayantamahata asked Apr 7, 2018 jjayantamahata 441 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shiva Sagar Rao commented May 7, 2021 reply Follow Share https://gateoverflow.in/321862/isi2015-mma-15 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes graph 1 : ${(9/10)}^x$ graph 2: $ -3 +x -x^2$ There is no intersection point, it has no real solution. pankaj_vir answered Apr 7, 2018 pankaj_vir comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer is (C)1 jjayantamahata answered Apr 7, 2018 jjayantamahata comment Share Follow See all 2 Comments See all 2 2 Comments reply pankaj_vir commented Apr 7, 2018 reply Follow Share I don't think is 1. 0 votes 0 votes ankitgupta.1729 commented Apr 7, 2018 reply Follow Share answer should be 0.. (9/10)x = -(x2 - x + 3) (9/10)x = -[(x-(1/2))2 + 11/4] -(9/10)x = (x-(1/2))2 + 11/4 -(0.9)x = (x-(1/2))2 + 11/4 here , -(0.9)x will always give negative values..so its graph will be below X-axis and (x-(1/2))2 + 11/4 is upward parabola which always give positive values..So, its graph will be above X-axis.. So, both graphs will never cut each other..So, no real solution will be existed.. 2 votes 2 votes Please log in or register to add a comment.