27 votes 27 votes The minimum number of $\text{D}$ flip-flops needed to design a mod-258 counter is 9 8 512 258 Digital Logic gatecse-2011 digital-logic normal digital-counter + – go_editor asked Sep 29, 2014 • edited Jul 29, 2015 go_editor 15.0k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments srestha commented Aug 4, 2018 reply Follow Share how same? pattern different for both One have 1 input another 2 input https://gateoverflow.in/8054/gate2015-2-7 0 votes 0 votes srestha commented Aug 4, 2018 reply Follow Share https://gateoverflow.in/84803/self-doubt-modulus-counter 0 votes 0 votes Mk Utkarsh commented Aug 4, 2018 reply Follow Share An n-bit binary counter consists of n flip-flops and can count in binary from 0 to 2^n - 1. -Morris Mano (Digital logic and computer design) whether we use JK or D flipflops the number of flip flops will not change. 4 votes 4 votes Please log in or register to add a comment.
1 votes 1 votes An n-bit binary counter consists of n flip-flops and can count in binary from 0 to 2^n-1 2^n ≥ 258 heena singh answered Nov 27, 2017 heena singh comment Share Follow See all 0 reply Please log in or register to add a comment.
–1 votes –1 votes answer - A ankitrokdeonsns answered Oct 19, 2014 ankitrokdeonsns comment Share Follow See 1 comment See all 1 1 comment reply smartmeet commented Feb 4, 2017 reply Follow Share If we want to buid with JK and T ffs then they are also '9' or something different? 0 votes 0 votes Please log in or register to add a comment.