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If the difference between the expectation of the square of a random variable $\left(E\left[X^2\right]\right)$ and the square of the expectation of the random variable $\left(E\left[X\right]\right)^2$ is denoted by $R$, then

1. $R=0$
2. $R<0$
3. $R\geq 0$
4. $R > 0$
edited | 1.6k views
+3

This might help ....

0
Catch is that Variance can never be negative.
0
Unless we are dealing with numbers with imaginary parts!

The difference between  $(E[X²])$ and $($$E[X]$$)$$^{2}$ is called variance of a random variable. Variance measures how far a set of numbers is spread out. (A variance of zero indicates that all the values are identical.) A non-zero variance is always positive.

answered by Loyal (8.8k points)
edited

V(x) = E(x^2) - [E(x)]= R

where V(x) is the Variance of x, Since Variance is Square and Hence Never be Neagtive, R>=0

answered by Junior (593 points)
answered by Loyal (8.8k points)

answer is option c .

answered ago by Active (1.4k points)

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