using $(a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2(ab+bc+ca)$;
$a^{2} + b^{2} + c^{2} = (a + b + c)^{2} - 2(ab+bc+ca) $
For Equation of the form, $\alpha x^{3} + \beta x^{2} + \gamma x + \delta$,
$a+b+c = -\frac{\beta }{\alpha }$
and $ab+bc+ac = \frac{\gamma }{\alpha }$
So clearly its equal to 9-2*2 = 5;
Ans = 5