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 In an n- CPU shared bus system, if z is the probability that any CPU requests the bus in a given cycle, the probability that only one CPU uses the bus is given by-

A. Nz(1-z)n-1 

B. Z(1-z)n-1

C. N(1-z)n

D. (N-1)z(1-z)n

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OPTION A.

There are N - CPUs , and exactly one of them uses the bus.

Using binomial distribution, nCx  * px * (1- p)n-x  

                  { Here x is number of success , p is probability of success in one trial,

                    n is total number of trials }   


probability that only one CPU uses the bus  =  NC* z* (1-z)N-1   = A(Ans)  

                      {Here z is probability  of CPU using bus & we want exactly one Cpu to use the bus

                        at a time so,   NC}..

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